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FaggyDiman's questions

Martin Hope
FaggyDiman
Asked: 2025-01-22 01:18:05 +0000 UTC
  • 6

再会。有一个简单的Python游戏“Life”的代码。

import pygame
import random
import time
clock = pygame.time.Clock()


background_colour = (0,0,0) #Цвет фона
cell_color = (255,255,255) #Белый цвет клеток
PADDING = 25 #Отступ от краёв
(width, height) = (1200, 700) #Ширина и высота поля
screen = pygame.display.set_mode((width, height)) #Конструкт экрана(поверхности)
pygame.display.set_caption('CELLS') #Название программы
screen.fill(background_colour) #Залить фон

cell_array=[] #Список клеток со значениями [Отн.позиц.X ; Отн.позиц.Y ; Состояние]
blockSize = 2


def initGrid(): #Первичная инициализация клеточного поля
  global blockSize
  global PADDING
  for x in range(PADDING, width-PADDING-blockSize,blockSize+1):
    for y in range(PADDING, height-PADDING-blockSize,blockSize+1):
      if x > width//2-300 and y > height//2-300 and x < width//2+300 and y < height//2+300:
        if random.random() < 0.3:
          initState=1
          cell_array.append([(x - PADDING) // (blockSize + 1), (y - PADDING) // (blockSize + 1), initState])
        else:
          initState=0
      else:
        initState = 0
        cell_array.append([(x-PADDING)//(blockSize+1),(y-PADDING)//(blockSize+1),initState])

def drawGrid():
  global blockSize
  global PADDING
  for state in cell_array:
    if state[2] == 1 :
      #rect = pygame.Rect((state[0]+PADDING)*(blockSize+1),(state[1]+PADDING)*(blockSize+1), blockSize, blockSize
      rect = pygame.Rect(
        (state[0] * (blockSize+1)) + PADDING, (state[1] * (blockSize+1) + PADDING),
        blockSize, blockSize
      )
      pygame.draw.rect(screen, cell_color, rect, 0)
    else:
      rect = pygame.Rect(
        (state[0] * (blockSize + 1)) + PADDING, (state[1] * (blockSize + 1) + PADDING),
        blockSize, blockSize
      )
      pygame.draw.rect(screen, background_colour, rect, 0)


def updateGeneration():
  global cell_array

  cell_dict = {(cell[0], cell[1]): cell[2] for cell in cell_array}

  new_cell_array = []

  for cell in cell_array:
    x, y, initState = cell
    neighbors = [
      (x + 1, y), (x - 1, y),
      (x, y + 1), (x, y - 1),
      (x + 1, y - 1), (x + 1, y + 1),
      (x - 1, y + 1), (x - 1, y - 1)
    ]

    live_neighbors = sum(1 for n in neighbors if cell_dict.get(n, 0) == 1)

    if initState == 1 and (live_neighbors < 2 or live_neighbors > 3):
      new_cell_array.append([x, y, 0])  # Клетка умирает
    elif initState == 0 and live_neighbors == 3:
      new_cell_array.append([x, y, 1])  # Клетка оживает
    else:
      new_cell_array.append([x, y, initState])  # Не меняем

  # Обновляем cell_array
  cell_array = new_cell_array

## ЦИКЛ ОТРИСОВКИ И ПРОВЕРКИ СОБЫТИЙ
initGrid()
running = True
while running:
  drawGrid()
  pygame.display.flip() ## Обновить экран
  updateGeneration()
  clock.tick(30)
  for event in pygame.event.get():  ## Обработать кнопку выхода
    if event.type == pygame.QUIT:
      running = False

然而，问题是，由于某种原因，死亡的细胞不会复活，最常见的形状是角，尽管根据规则应该出现 4x4 的盒子。 图片

python