有一个 .txt 文件，其中包含一个带有转义的字符串\n。当在 python 中用 读取这个文件时，read()这个字符被转换为使用时s.encode('unicode_escape')（即\n变为\\\\n，解码时变为\\n）。我需要一种方法来阻止或扭转这种转变。
with open('../quotes/to_add.txt', 'r', encoding="UTF-8") as q:
q = q.read().splitlines()
文件示例：
Ну вот идут буковки буковки и тут хоп:\n- Начался диалог\n- Закончился
我需要在阅读后在屏幕上显示：
Ну вот идут буковки буковки и тут хоп:
- Начался диалог
- Закончился
有一个电报机器人根据时间表发送报价。添加到其lru_cache通过functools.
结果，用户收到了 3 次相同的报价（在不同的时间），尽管cache_clear()我在每次邮寄后都收到了。引号取自 MongoDB，这是我想要缓存的时刻，这样它就不会花一秒钟的时间。
class Quote:
@lru_cache(maxsize=19)
def check(self, user: str, check=True) -> dict:
"""Checks for quote available for {user}"""
est_quotes = self.db.estimated_document_count()
if self.db.count_documents({"Users": user}) >= est_quotes - 1:
# removes user id from DB if there is no more available quotes for user
self.db.update_many({"Users": user}, {"$pull": {"Users": user}})
all_quotes = self.db.find({})
while True:
quote = all_quotes[random.randint(0, est_quotes - 1)]
if not check:
# if check for available is not required return random quote
return quote
if user in quote["Users"]:
continue
required_quote = quote
self.db.update_one({"Quote": quote["Quote"]}, {"$push": {"Users": user}})
return required_quote
def random(self, user, checking=False):
""" Sends random quote for user.
If checking == False, it does not check for the presence of id in the database.
"""
quo = self.check(user, check=checking)
keyboard = types.InlineKeyboardMarkup()
key_book = types.InlineKeyboardButton(text='📖', callback_data='book', url=quo["URL"])
keyboard.add(key_book)
# key_like = types.InlineKeyboardButton(text='Нет', callback_data='no')
# keyboard.add(key_like)
bot.send_message(user,
text=f'<i>{quo["Quote"]}\n</i>\n<b>{quo["Book"]}</b>\n#{quo["Author"]}',
parse_mode='HTML', reply_markup=keyboard)
def randoms(self, group: int):
"""Sends random quote for users who aren't in 'stopped' list"""
start_time = time.time()
counter = 0
with open(f'users{group}', 'r') as users_r:
r = users_r.read().splitlines()
print("=================================")
for user_id in r:
if user_id in self.stopped:
continue
try:
self.random(str(user_id), True)
print(f"Latency #{counter}: {str(time.time() - start_time)[:4]} seconds")
except telebot.apihelper.ApiTelegramException as e:
print(f"Bad ID ({user_id}):", e)
except Exception as e:
print(e)
finally:
counter += 1
self.check.cache_clear()
很可能，我只是不太了解缓存的方式和内容，但我请您为我的问题提出最佳解决方案。
@bot.callback_query_handler(func=lambda call: True)
def callback_worker(call):
keyboard = types.InlineKeyboardMarkup()
key_cancel = types.InlineKeyboardButton(text='Отменить', callback_data='cancel')
keyboard.add(key_cancel)
if call.data == "report":
bot.send_message(call.message.chat.id,
'<i>Опишите проблему, Ваше сообщение будет доставлено администрации и принято на рассмотрение!\n</i>',
parse_mode='HTML', reply_markup=keyboard)
if call.data == 'cancel':
bot.send_message(call.message.chat.id,
'<b><i>Отменено!</i></b>',
parse_mode='HTML')
else:
bot.register_next_step_handler(call.message, report_send)
elif call.data == "support":
bot.send_message(call.message.chat.id,
'<i>Опишите Вашу идею, сообщение будет доставлено администрации и принято на рассмотрение!\n</i>',
parse_mode='HTML', reply_markup=keyboard)
if call.data == 'cancel':
bot.send_message(call.message.chat.id,
'<b><i>Отменено!</i></b>',
parse_mode='HTML')
else:
bot.register_next_step_handler(call.message, support_send)
我需要当按钮被按下时，cancel函数（support_send() или report_send()）的执行停止，或者在用户写消息之前它根本不启动。使用异步库是可能的，但不可取。
有这样一个“迭代器”：
class MyIterator():
def __init__(self, lst):
self.lst = lst
self.counter = 0
def __next__(self):
try:
z = self.lst[self.counter]
self.counter += 2
return z
except:
raise StopIteration
出现错误后，它会输出以下内容：
Traceback (most recent call last):
File "C:/BookBot/test.py", line 10, in __next__
z = self.lst[self.counter]
IndexError: list index out of range
During handling of the above exception, another exception occurred:
Traceback (most recent call last):
File "C:/BookBot/test.py", line 22, in <module>
print(next(x))
File "C:/BookBot/test.py", line 14, in __next__
raise StopIteration
StopIteration
问题：如何做到这一点，只有StopIteration，有可能做到这一点吗？
我试图找出问题所在，但我并没有真正找到关于角色自动分配错误的任何内容。它不会给控制台任何错误，它只是不响应用户进入服务器。
@bot.event
async def on_member_join(member):
new = discord.utils.get(member.guild.roles, id=767446695294140426)
channel = discord.utils.get(member.channel, id=767470344189247590)
await member.add_roles(new)
await channel.send(f"{member.mention} joined to channel!")
在这段代码中，我需要确定给定的角色 ID 是否在作者角色列表中。角色 ID - 767450270888099910
@bot.command()
async def report(ctx, player: discord.Member, *args):
author = ctx.message.author
if 767450270888099910 in author.roles:
await ctx.send('Предателям не давали право открывать рот! Скажи спасибо что ты можешь остаться на сервере...')
return True