spl33t's questions

有两个数组需要通过相同的键值连接，第一个表中的 [SteamID64] 和第二个表中的 [steamid]。在第一个数组中，[SteamID64] 可能与示例中的相同，我只是描述了这种情况。

第一个数组

$arr1 = [
    '0' => [
        "PlayerID" => "1",
        "User" => "lexa",
        "Time" => "300",
        "SteamID64" => "76561198170801830",
        "SteamID" => "STEAM_0:0:105268051"
    ],
    '1' => [
        "PlayerID" => "1",
        "User" => "lexa",
        "Time" => "250",
        "SteamID64" => "76561198170801830",
        "SteamID" => "STEAM_0:0:105268051"
    ],
    '2'=> [
        'PlayerID' => "5",
        'User' => "Player",
        "Time" => "400",
        'SteamID64' => "76561199604582870",
        'SteamI' => "STEAM_0:0:822158571"
    ],
    '3' => [
        "PlayerID" => "4",
        "User" => "idfyau",
        "Time" => "360",
        "SteamID64" => "76561198161729178",
        "SteamID" => "STEAM_0:0:100731725"
    ]
];

第二个数组

$arr2 = [
    '76561198170801830'=> [
      "steamid" => "76561198170801830",
      "personaname" => "Black_Mens___",
      "profileurl" => "https://steamcommunity.com/id/3523557555/",
      "avatar" => "https://steamcdn-a.akamaihd.net/steamcommunity/public/images/avatars/64/64d96db5c4a160205149bbfab2ccdbc7c3bad688.jpg"
    ],
    '76561198161729178'=> [
        "steamid"=> "76561198161729178",
        "personaname"=> "ак4ОнаиД",
        "profileurl"=> "https://steamcommunity.com/id/dfhfdj/",
        "avatar"=> "https://steamcdn-a.akamaihd.net/steamcommunity/public/images/avatars/bf/bfa372987ba46f33b75ea1078e5b0a0a001cb2d8.jpg"
    ]     
];

[PlayerID] => 5 的玩家的期望结果* 没有找到对，所以他按原样进入结果。

$data = [
    '0' => [
        "PlayerID" => "1",
        "User" => "lexa",
        "Time" => "300",
        "SteamID64" => "76561198170801830",
        "SteamID" => "STEAM_0:0:105268051",
        "personaname" => "Black_Mens___",
        "profileurl" => "https://steamcommunity.com/id/3523557555/",
        "avatar" => "https://steamcdn-a.akamaihd.net/steamcommunity/public/images/avatars/64/64d96db5c4a160205149bbfab2ccdbc7c3bad688.jpg"   
    ],
    '1' => [
        "PlayerID" => "1",
        "User" => "lexa",
        "Time" => "250",
        "SteamID64" => "76561198170801830",
        "SteamID" => "STEAM_0:0:105268051",
        "personaname" => "Black_Mens___",
        "profileurl" => "https://steamcommunity.com/id/3523557555/",
        "avatar" => "https://steamcdn-a.akamaihd.net/steamcommunity/public/images/avatars/64/64d96db5c4a160205149bbfab2ccdbc7c3bad688.jpg"   
    ],
    '2'=> [
        'PlayerID' => "5",
        'User' => "Player",
        "Time" => "400",
        'SteamID64' => "76561199604582870",
        'SteamI' => "STEAM_0:0:822158571"
    ],
    '3' => [
        "PlayerID" => "4",
        "User" => "idfyau",
        "Time" => "360",
        "SteamID64" => "76561198161729178",
        "SteamID" => "STEAM_0:0:100731725",
        "personaname" => "ак4ОнаиД",
        "profileurl" => "https://steamcommunity.com/id/dfhfdj/",
        "avatar" => "https://steamcdn-a.akamaihd.net/steamcommunity/public/images/avatars/bf/bfa372987ba46f33b75ea1078e5b0a0a001cb2d8.jpg"
    ]
];

现在我这样做：

    foreach ($arr1 as $key => $row1) {
        foreach ($arr2 as $key => $row2) {
            if($row1['SteamID64'] == $row2['steamid'] ){
                $row1['SteamID64'] = $row2['steamid'];
                $row1['personaname'] = $row2['personaname'];
                $row1['profileurl'] = $row2['profileurl'];
                $row1['avatar'] = $row2['avatar'];
                $row1['avatarmedium'] = $row2['avatarmedium'];
                $row1['avatarfull'] = $row2['avatarfull'];
                $data[] = $row1;
                break;
            }
        }
    }

我得到这个对于具有 [PlayerID] => 5 的玩家没有找到对，他不在结果中

$data = [
    '0' => [
        "PlayerID" => "1",
        "User" => "lexa",
        "Time" => "300",
        "SteamID64" => "76561198170801830",
        "SteamID" => "STEAM_0:0:105268051"
        "personaname" => "Black_Mens___"
        "profileurl" => "https://steamcommunity.com/id/3523557555/"
        "avatar" => "https://steamcdn-a.akamaihd.net/steamcommunity/public/images/avatars/64/64d96db5c4a160205149bbfab2ccdbc7c3bad688.jpg"   
    ],
    '1' => [
        "PlayerID" => "1",
        "User" => "lexa",
        "Time" => "250",
        "SteamID64" => "76561198170801830",
        "SteamID" => "STEAM_0:0:105268051"
        "personaname" => "Black_Mens___"
        "profileurl" => "https://steamcommunity.com/id/3523557555/"
        "avatar" => "https://steamcdn-a.akamaihd.net/steamcommunity/public/images/avatars/64/64d96db5c4a160205149bbfab2ccdbc7c3bad688.jpg"   
    ],
    '2' => [
        "PlayerID" => "4",
        "User" => "idfyau",
        "Time" => "360",
        "SteamID64" => "76561198161729178",
        "SteamID" => "STEAM_0:0:100731725"
        "personaname" => "ак4ОнаиД"
        "profileurl" => "https://steamcommunity.com/id/dfhfdj/"
        "avatar" => "https://steamcdn-a.akamaihd.net/steamcommunity/public/images/avatars/bf/bfa372987ba46f33b75ea1078e5b0a0a001cb2d8.jpg"
    ]
];

我的代码的问题是，只有找到一对的人才能进入结果。我想得到所有有和没有对子的玩家，正如我在期望的结果中显示的*.

有几个具有不同数量元素的列表。您需要计算每个列表中有多少元素，如果只有一个元素，则隐藏此列表上方的标题。这是我的列表和脚本的示例：

$('.category-group-list ul.list').each(function() {
  if ($(this).childElementCount == 1) {
    $("h4").addClass('hide');
  }
});

<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>

<div class="category-group-list">
  <h4>Арматура Ат100</h4>
  <ul class="list">
    <li class="list-item">Арматура Ат100</li>
  </ul>
</div>

<div class="category-group-list">
  <h4>Арматура</h4>
  <ul class="list">
    <li class="list-item">Арматура Ат800</li>
    <li class="list-item">Арматура Ат800</li>
    <li class="list-item">Арматура Ат800</li>
  </ul>
</div>

<div class="category-group-list">
  <h4>Арматура Ат800</h4>
  <ul class="list">
    <li class="list-item">Арматура Ат800</li>
  </ul>
</div>


<div class="category-group-list">
  <h4>Арматура</h4>
  <ul class="list">
    <li class="list-item">Арматура Ат800</li>
    <li class="list-item">Арматура Ат800</li>
    <li class="list-item">Арматура Ат800</li>
    <li class="list-item">Арматура Ат800</li>
  </ul>
</div>

玩的很开心！

任务是在当前嵌套级别显示子类别和这些类别中的产品的列表。

有一个代码显示忽略活动类别的所有商店类别。

                $args = array(

   'number'     => $number,

   'orderby'   => 'title',

   'order'     => 'ASC',

   'hide_empty' => $hide_empty,

   'include'   => $ids,
                  


);

$product_categories = get_terms( 'product_cat', $args );

$count = count($product_categories);

if ( $count > 0 ){

   foreach ( $product_categories as $product_category ) {

       echo '<h4><a href="' . get_term_link( $product_category ) . '">' . $product_category->name . '</a></h4>';

       $args = array(

           'posts_per_page' => -1,

           'tax_query' => array(

              'relation' => 'AND',

               array(

                   'taxonomy' => 'product_cat',

                   'field' => 'slug',

                   // 'terms' => 'white-wines'

                   'terms' => $product_category->slug

                )

           ),

           'post_type' => 'product',

           'orderby' => 'title,'

       );

       $products = new WP_Query( $args );

       echo "<ul>";

       while ( $products->have_posts() ) {

           $products->the_post();

           ?>

               <li>

                   <a href="<?php the_permalink(); ?>">

                       <?php the_title(); ?>

                   </a>

               </li>

           <?php

       }

       echo "</ul>";

   }

}

?>

有个理解是需要获取活动类别的ID，获取我需要的列表，但是我的php知识不足以实现这个。我挖出了这样一个代码，还有待了解如何在上述代码中正确应用它。

$current_term = get_queried_object();
    $terms = get_terms( [
        'taxonomy' => [ 'product_cat' ],
        'parent'         => $current_term->term_id,
    ] );
var_dump( $terms );

我希望得到您的提示，结果应该类似于以下结构：

商店 > 产品（活跃类别）

水果（儿童类别）

• 香蕉（产品）
• 苹果
• 梨

蔬菜

• 土豆
• 洋葱
• 胡椒

有两个 Google 表格，每个表格的行数和排序方式不同，有一个“文章”列。只需要提取与文章匹配的行并以这种形式呈现以进行价格比较：