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主页 / 问题 / 961833
Accepted
Егор Глухов
Егор Глухов
Asked:2020-03-27 09:22:18 +0000 UTC2020-03-27 09:22:18 +0000 UTC 2020-03-27 09:22:18 +0000 UTC

无法为类创建转换器

  • 772

我正在尝试从收到的 JSON 数据创建一个数据库

const val CURRENT_USER_ID = 0

@Entity(tableName = "current_user")
data class User_new(
    @SerializedName("avatar")
    val avatar: String,
    @SerializedName("balance")
    val balance: Double,
    @SerializedName("id")
    val id_user: Int,
    @SerializedName("login")
    val login: String,
    @SerializedName("not_adult")
    val notAdult: Int,
    @SerializedName("token")
    val token: String
){
    @PrimaryKey(autoGenerate = false)
    var id: Int = CURRENT_USER_ID
}

此处使用数据类

   data class authClient(
    @SerializedName("msg")
    val msg: String,
    @SerializedName("response")
       val user: User_new,
    @SerializedName("status")
    val status: String
)

基础创建

@Dao
interface CurrentUserDao {

    @Insert(onConflict = OnConflictStrategy.REPLACE)
    fun upset(weatherEntry: User_new)

    @Query("select * from current_user where id = $CURRENT_USER_ID")
    fun getGlavsMetric(): LiveData<ImperialCurrentUserEntry>
}

ImperialCurrentUserEntry

data class ImperialCurrentUserEntry(
    @ColumnInfo(name = "avatar")
    override val avata_user: String,
    @ColumnInfo(name = "balance")
    override val balance_user: Double,
    @ColumnInfo(name = "id_user")
    override val id_user_a: Int,
    @ColumnInfo(name = "login")
    override val login_user: String,
    @ColumnInfo(name = "notAdult")
    override val notAdult_user: Int,
    @ColumnInfo(name = "token")
    override val token_user: String
):UnitSpecificCurrentUser

预测数据库

@Database(
    entities = [User_new::class],
    version = 1
)
abstract class ForecastDatabase : RoomDatabase() {
    abstract fun currentGlavsDao():CurrentUserDao

    companion object {
        @Volatile private var instance: ForecastDatabase? = null
        private val LOCK = Any()

        operator fun invoke(context: Context) = instance ?: synchronized(LOCK){
            instance ?: buildDatabase(context).also { instance = it}
        }

        private fun buildDatabase(context: Context)=
                Room.databaseBuilder(context.applicationContext,
                    ForecastDatabase::class.java, "forecast.db")
                    .build()
    }
}

像这样打电话

    GlobalScope.launch(Dispatchers.Main) {
        val textcurrent = apiServer
            .getAuth("Login","Pass").await()

        textView.text = textcurrent.user.toString()
    }

启动程序并获取链接后出现错误 错误

对这个代码发誓

val textcurrent = apiServer
            .getAuth("Login","Pass").await()

很抱歉文字很多,请帮忙

android
  • 1 1 个回答
  • 10 Views

1 个回答

  • Voted
  1. Best Answer
    Егор Глухов
    2020-03-28T02:01:46Z2020-03-28T02:01:46Z

    名称错误var Id

    const val CURRENT_USER_ID = 0
    
    @Entity(tableName = "current_user")
    data class User_new(
        @SerializedName("avatar")
        val avatar: String,
        @SerializedName("balance")
        val balance: Double,
        @SerializedName("id")
        val id_user: Int,
        @SerializedName("login")
        val login: String,
        @SerializedName("not_adult")
        val notAdult: Int,
        @SerializedName("token")
        val token: String
    ){
        @PrimaryKey(autoGenerate = false)
        var id: Int = CURRENT_USER_ID
    }
    

    因为摘要已经有了标题id

    @SerializedName("id")
    val id_user: Int,
    

    您只需要将名称替换为var idvarid_currect

    • 0

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