我将立即显示代码,然后是问题:
class Callme{
void call(String msg){
System.out.print("[" + msg);
try {
Thread.sleep(100);
}catch (InterruptedException e){
System.out.println("Прервано!");
}
System.out.println("]");
}
}
class Caller implements Runnable{
String msg;
Callme target;
Thread t;
public Caller (Callme targ, String s){
target = targ;
msg = s;
t = new Thread(this);
t.start();
}
public void run(){
synchronized (target){
target.call(msg);
}
}
}
public class Example {
public static void main(String[] args) {
Callme target = new Callme();
Caller ob1 = new Caller(target, "Один");
Caller ob2 = new Caller(target, "Два");
Caller ob3 = new Caller(target, "Три");
try {
ob1.t.join();
ob2.t.join();
ob3.t.join();
}catch (InterruptedException e){
System.out.println("Прервано!");
}
}
}
我正在学习Java中的线程。面临对Caller类的一个元素的误解,即:Callme目标;它是对类类型的引用吗?它是如何工作的?为什么是她?为什么变量类型是Callme?我很困惑(
在构造函数原型中
Caller(Callme targ)- 你定义了一个targtype的参数Callme,这意味着当访问构造函数时Caller,你需要Callme像这样传递一个类的对象:new Caller(new Callme())- wheretarg- 将是传递的对象Callme。