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Narnik Gamarnik
Asked:2020-07-08 16:11:03 +0000 UTC2020-07-08 16:11:03 +0000 UTC

QuerySet ManyToMany 和列表​​生成器

  • 772

所以我创建了两个列表：

devices = []
for i in context['services']:
    for z in i.devices.all():
        devices.append(z)

spare_parts = []
for i in context['services']:
    for z in i.spare_parts.all():
        spare_parts.append(z)

为了简洁和美观，我想使用生成器来实现，但它不起作用。

我正在尝试这样做：

[k for k in [[z for z in i.devices.all()] for i in context['services']]]
[k for k in [[z for z in i.spare_parts.all()] for i in context['services']]]

但我得到这个结果：

[[<Device: asdasd>], []]
[[], []]

你需要这样的东西：

[<Device: asdasd>]
[]

无论你用生成器尝试什么方法，总会有额外的括号。几乎在任何情况下，我都会得到一个列表QuerySet'ов

python-3.x

1 个回答

  1. Best Answer

    也这样觉得

    devices = [z for i in context['services'] for z in i.devices.all()]
share_parts = [z for i in context['services'] for z in i.spare_parts.all()]
    • 1

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