主页 / 问题 / 625652
Accepted
Senior Pomidor
Asked:2020-02-09 20:46:23 +0000 UTC2020-02-09 20:46:23 +0000 UTC

POST xml 错误请求 400

  • 772

有一个 XML 文件 match.xml，很容易通过 curl 发送 POST 并将其添加到数据库中。

curl -F "xml=@match.xml" web_url

Java 的标准 POST 实现返回 POST 响应代码::400 错误请求

public static void sendPOST(String data) throws IOException {
    URL obj = new URL(FinalConstants.BETRADAR_UPLOAD);
    HttpURLConnection con = (HttpURLConnection) obj.openConnection();
    con.setRequestMethod("POST");
    con.setRequestProperty("User-Agent", USER_AGENT);

    // For POST only - START
    con.setDoOutput(true);
    OutputStream os = con.getOutputStream();
    os.write(data.getBytes());
    os.flush();
    os.close();
    // For POST only - END

    int responseCode = con.getResponseCode();
    System.out.println("POST Response Code :: " + responseCode);

    if (responseCode == HttpURLConnection.HTTP_OK) { //success
        BufferedReader in = new BufferedReader(new InputStreamReader(
                con.getInputStream()));
        String inputLine;
        StringBuffer response = new StringBuffer();

        while ((inputLine = in.readLine()) != null) {
            response.append(inputLine);
        }
        in.close();

        // print result
        System.out.println(response.toString());
    } else {
        System.out.println("POST request not worked");
    }
}

并使用这样的设置返回相同的错误

        httpURLConnection.setReadTimeout(10000);
        httpURLConnection.setConnectTimeout(15000);
        httpURLConnection.setRequestMethod("POST");
        httpURLConnection.setRequestProperty("Content-Type", "text/xml");


        httpURLConnection.setDoInput(true);
        httpURLConnection.setDoOutput(true);

告诉我它是如何工作的curl -F？如何正确发送数据？

更新程序

我用 HttpClient 尝试了几个选项，它们都提供了以下内容

HttpResponseProxy{HTTP/1.1 400 错误请求 [服务器：nginx，日期：2017 年 2 月 9 日星期四 20:07:18 GMT，内容类型：应用程序/八位字节流，内容长度：0，连接：保持活动状态]}

1个选项

    HttpClient client = new DefaultHttpClient();
    HttpPost post = new HttpPost(FinalConstants.UPLOAD);
    HttpEntity entity =
            new ByteArrayEntity(data.getBytes("UTF-8"),
                    ContentType.TEXT_XML); 
    post.setEntity(entity);
    HttpResponse response = client.execute(post);
    String result = EntityUtils.toString(response.getEntity());

选项 2

InputStream in ;
StringEntity entity = new StringEntity(data, ContentType.create(
    "text/xml", Consts.UTF_8));
entity.setChunked(true);
HttpPost httppost = new HttpPost( FinalConstants.UPLOAD);

httppost.setEntity(entity);

HttpClient client = HttpClients.createDefault();
HttpResponse response = client.execute(httppost);
System.out.println(response.toString());
in=response.getEntity().getContent();
String body = IOUtils.toString(in);
System.out.println(body);

也是使用该文件的变体

builder.addBinaryBody(
    "file",
    new FileInputStream(f),
    ContentType.APPLICATION_OCTET_STREAM, // Также как и с другими типами 
    f.getName()
);

都一样，我想发送一个字符串，而不是一个文件

UPD2 

public static void sendPOST(File file) throws IOException {
    try (CloseableHttpClient httpClient = HttpClients.createDefault()) {
        final HttpPost uploadFile = new HttpPost(FinalConstants.UPLOAD);
        final HttpEntity entity = MultipartEntityBuilder
                .create()
                .addBinaryBody("xml", file).build();
        uploadFile.setEntity(entity);
        final HttpResponse response = httpClient.execute(uploadFile);
        System.out.println(EntityUtils.toString(response.getEntity()));
    }
}


java.lang.NoSuchMethodError: org.apache.http.entity.ContentType.create(Ljava/lang/String;[Lorg/apache/http/NameValuePair;)Lorg/apache/http/entity/ContentType;

    at org.apache.http.entity.mime.MultipartEntityBuilder.buildEntity(MultipartEntityBuilder.java:219)
    at org.apache.http.entity.mime.MultipartEntityBuilder.build(MultipartEntityBuilder.java:240)
java

1 个回答

  1. Best Answer

    curl -F模拟发送 HTTP 表单，"xml=@match.xml"- 附加具有指定名称的文件。
    对于此类 HTTP 请求（带有附件），Content-Type 必须是multipart/form-data，并且此类请求的一部分（部分）必须具有名称xml（对于您的示例）并包含具有相应 Content-Type 的文件.
    老实说，正如问题评论中已经建议的那样，使用 Apache 的 HttpClient 库更容易。
    有很多关于如何multipart/form-data使用 HttpClient 发送的示例，这是来自 Google 的第一个示例：https ://stackoverflow.com/questions/1378920/how-can-i-make-a-multipart-form-data-post-请求使用java

    编辑：此代码提供与相同的查询curl -F "xml=@match.xml" web_url 

        try (CloseableHttpClient httpClient = HttpClients.createDefault()) {
        final HttpPost uploadFile = new HttpPost("web_url");
        final HttpEntity entity = MultipartEntityBuilder.create().addBinaryBody("xml", new File("match.xml")).build();
        uploadFile.setEntity(entity);
        final HttpResponse response = httpClient.execute(uploadFile);
        System.out.println(EntityUtils.toString(response.getEntity()));
    }

    您还需要添加以下依赖项（Maven）：

    <dependency>
        <groupId>org.apache.httpcomponents</groupId>
        <artifactId>httpclient</artifactId>
        <version>4.5.3</version>
    </dependency>
    <dependency>
        <groupId>org.apache.httpcomponents</groupId>
        <artifactId>httpmime</artifactId>
        <version>4.5.3</version>
    </dependency>
    • 1

相关问题