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主页 / 问题 / 1088022
Accepted
dbUser11
dbUser11
Asked:2020-02-27 13:07:53 +0000 UTC2020-02-27 13:07:53 +0000 UTC 2020-02-27 13:07:53 +0000 UTC

数组元素显示不正确

  • 772

我想显示用户填写的数组元素。我想将输出组织为矩阵。问题是这不会发生。虽然,水,逻辑上一切都是如此。可能是什么问题呢?

输入:

Введите число строк 1-й матрицы - A (<=50)--> 2
Введите число столбцов 1-й матрицы - A (<=50)--> 2
Введите число столбцов 2-й матрицы - B (<=50)--> 2
Введите 1-ю матрицу (A):
Введите A[1,1] --> 1
Введите A[1,2] --> 2
Введите A[32,1] --> 
Введите A[2,2] --> 4
Введите 2-ю матрицу (B):
Введите B[1,1] --> 5
Введите B[1,2] --> 6
Введите B[2,1] --> 6
Введите B[2,2] --> 6

结论:

Матрица А.
[1,2,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0]  [1,2,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0]Матрица А.
[1,2,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0]  [3,4,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0]Матрица А.
[3,4,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0]  [1,2,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0]Матрица А.
[3,4,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0]  [3,4,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0]Матрица B.
[5,6,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0]  [5,6,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0]Матрица B.
[5,6,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0]  [6,6,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0]Матрица B.
[6,6,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0]  [5,6,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0]Матрица B.
[6,6,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0]  [6,6,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0]
---- Результат: -----
   17.00   18.00
   39.00   42.00

编码:

Const Max=50;

Var AA,BB,CC: array [1..Max,1..Max] of Double;
  ii,jj,kk,nn,mm,ll : integer; Summa: double;

begin
  write('Введите число строк 1-й матрицы - A (<=50)--> ');readln(NN);
  write('Введите число столбцов 1-й матрицы - A (<=50)--> ');readln(KK);
  write('Введите число столбцов 2-й матрицы - B (<=50)--> ');readln(MM);
  writeln('Введите 1-ю матрицу (A):');
  for ii:=1 to nn do
  for jj:=1 to kk do
    begin
      write('Введите A[',ii,',',jj,'] --> ');
      readln(AA[ii,jj]);
    end;

  writeln('Введите 2-ю матрицу (B):');
  for ii:=1 to kk do
  for jj:=1 to mm do
   begin write('Введите B[',ii,',',jj,'] --> '); readln(BB[ii,jj]);
   end;

   {проблема}
   for ii:=1 to nn do
   for jj:=1 to kk do
   begin
     writeln('Матрица А.');
     write(AA[ii], '  ', AA[jj]);
   end;

   for ii:=1 to kk do
   for jj:=1 to mm do
   begin
     writeln('Матрица B.');
     write(BB[ii], '  ', BB[jj]);
   end;

  {Вычисляем элементы матрицы-результата}

    for ii:=1 to nn do
    for jj:=1 to mm do
      begin
        Summa:= 0;
        for ll:= 1 to kk do
          Summa:= Summa + AA[ii,ll]*BB[ll,jj];
          CC[ii,jj] := Summa;
      end;
{Выводим матрицу-результат:}
  writeln();
  writeln('---- Результат: -----');
  for ii:=1 to nn do
    begin
      for jj:=1 to mm do
        write(CC[ii,jj]:8:2);
      writeln;
    end;
readln;
end.
массивы
  • 1 1 个回答
  • 10 Views

1 个回答

  • Voted
  1. Best Answer
    MBo
    2020-02-27T13:31:17Z2020-02-27T13:31:17Z

    矩阵是二维的,但是这会将矩阵的write(AA[ii], ' ', AA[jj]);两行作为一个整体显示——总大小为50。只显示必要的元素

     writeln('Матрица А.');
     for ii:=1 to nn do begin
       for jj:=1 to kk do
         write(AA[ii, jj], ' ');
       writeln;
     end;
    

    PS 另一个这样的时刻 - 在存在两位数的情况下,例如数字,格式化将失败。因此,最好在固定宽度的字段中使用输出。

    write(AA[ii, jj]: 4);
    
    • 1

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