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Martin Hope
Flevtek
Asked: 2025-01-05 07:42:39 +0000 UTC
  • 5

我想为计算器实现一个 dms() 函数，类似于 Windows 计算器。为了计算结果，我在最终公式所在行使用 sympy.N() 方法。我想看到这样的代码：

from sympy import N
def do_smth(x):
    return x+1
result = N('do_smth((8*7)-3)')

我应该如何实施这个？请求：如果你知道更好的使用Sympy库的方法，不要在评论中写下我不知道Sympy之类的。建议您的选择。

python
Martin Hope
Lennet8002
Asked: 2025-01-05 01:09:57 +0000 UTC
  • 1

我决定将我的《魔兽争霸》机器人放在GUI上。
我使用 Qt Designer 创建了界面并将其转换为 Python 代码。

现在问题来了。
屏幕截图显示了我的机器人（目前只有 gui 图片），我需要将输入的信息传递到变量中，user_info
如何做到这一点？

在此输入图像描述

所有GUI代码：

from PyQt5 import QtCore, QtGui, QtWidgets


class Ui_MainWindow(object):
    def setupUi(self, MainWindow):
        MainWindow.setObjectName("MainWindow")
        MainWindow.resize(349, 471)
        self.centralwidget = QtWidgets.QWidget(MainWindow)
        self.centralwidget.setObjectName("centralwidget")
        self.buttonspel = QtWidgets.QLabel(self.centralwidget)
        self.buttonspel.setGeometry(QtCore.QRect(10, 280, 121, 21))
        self.buttonspel.setObjectName("buttonspel")
        self.xhekpail = QtWidgets.QRadioButton(self.centralwidget)
        self.xhekpail.setGeometry(QtCore.QRect(10, 240, 211, 21))
        self.xhekpail.setObjectName("xhekpail")
        self.start = QtWidgets.QPushButton(self.centralwidget)
        self.start.setGeometry(QtCore.QRect(10, 310, 321, 61))
        self.start.setObjectName("start")
        self.buttonspel1 = QtWidgets.QKeySequenceEdit(self.centralwidget)
        self.buttonspel1.setGeometry(QtCore.QRect(130, 280, 81, 20))
        self.buttonspel1.setObjectName("buttonspel1")
        self.Lenbot = QtWidgets.QLabel(self.centralwidget)
        self.Lenbot.setGeometry(QtCore.QRect(10, 10, 281, 111))
        self.Lenbot.setObjectName("Lenbot")
        self.dushnim = QtWidgets.QLabel(self.centralwidget)
        self.dushnim.setGeometry(QtCore.QRect(20, 110, 291, 91))
        self.dushnim.setObjectName("dushnim")
        self.prochital = QtWidgets.QRadioButton(self.centralwidget)
        self.prochital.setGeometry(QtCore.QRect(10, 200, 82, 17))
        self.prochital.setObjectName("prochital")
        self.git = QtWidgets.QLabel(self.centralwidget)
        self.git.setGeometry(QtCore.QRect(10, 380, 291, 21))
        self.git.setObjectName("git")
        self.giturl = QtWidgets.QLabel(self.centralwidget)
        self.giturl.setGeometry(QtCore.QRect(10, 405, 221, 31))
        self.giturl.setObjectName("giturl")
        self.OBIZATELNO = QtWidgets.QLabel(self.centralwidget)
        self.OBIZATELNO.setGeometry(QtCore.QRect(220, 280, 81, 16))
        self.OBIZATELNO.setObjectName("OBIZATELNO")
        MainWindow.setCentralWidget(self.centralwidget)
        self.menubar = QtWidgets.QMenuBar(MainWindow)
        self.menubar.setGeometry(QtCore.QRect(0, 0, 349, 21))
        self.menubar.setObjectName("menubar")
        MainWindow.setMenuBar(self.menubar)

        self.retranslateUi(MainWindow)
        QtCore.QMetaObject.connectSlotsByName(MainWindow)
        
        
        self.add_functions()

    def retranslateUi(self, MainWindow):
        _translate = QtCore.QCoreApplication.translate
        MainWindow.setWindowTitle(_translate("MainWindow", "Len.bot"))
        self.buttonspel.setText(_translate("MainWindow", "введите кнопку спэла"))
        self.xhekpail.setText(_translate("MainWindow", " посмотреть что будер рыспылено"))
        self.start.setText(_translate("MainWindow", "СТАРТ"))
        self.Lenbot.setText(_translate("MainWindow", "<html><head/><body><p align=\"center\"><span style=\" font-weight:600; font-style:italic;\">Len.bot - новый бот, который упрощает гейм-</span></p><p align=\"center\"><span style=\" font-weight:600; font-style:italic;\">плей нашей любимой игры.</span></p><p align=\"center\"><span style=\" font-weight:600; font-style:italic;\">Зачем нам делать нудное дело самим,</span></p><p align=\"center\"><span style=\" font-weight:600; font-style:italic;\">если есть этот бот?</span></p></body></html>" ))
        self.dushnim.setText(_translate("MainWindow", "<html><head/><body><p align=\"center\"><span style=\" font-size:10pt; font-style:italic;\">немного подушним,</span></p><p align=\"center\"><span style=\" font-size:10pt; font-style:italic;\">обязательно прочитай инструкцию,</span></p><p align=\"center\"><span style=\" font-size:10pt; font-style:italic;\">она лежит в папке с ботом</span></p></body></html>"))
        self.prochital.setText(_translate("MainWindow", "прочитал?????????"))
        self.git.setText(_translate("MainWindow", "<html><head/><body><p><span style=\" font-size:12pt; font-weight:600; font-style:italic;\">мой гитхаб-</span></p><p><span style=\" font-size:12pt;\"><br/></span></p></body></html>"))
        self.giturl.setText(_translate("MainWindow", "<html><head/><body><p><span style=\" font-size:10pt; font-weight:600;\">https://github.com/Lennet8002</span></p></body></html>"))
        self.OBIZATELNO.setText(_translate("MainWindow", "ОБЯЗАТЕЛЬНО!"))
        
    def add_functions(self):
        self.xhekpail.clicked.connect(self.pail_chek)    #запомнить 25минут
        self.start.clicked.connect(self.start_chek)
        self.buttonspel.
        
    def pail_chek(self):
        user_info = "yes"
        
    def start_chek(self):
        start = "enter"

if __name__ == "__main__":
    import sys
    app = QtWidgets.QApplication(sys.argv)
    MainWindow = QtWidgets.QMainWindow()
    ui = Ui_MainWindow()
    ui.setupUi(MainWindow)
    MainWindow.show()
    sys.exit(app.exec_())
python
Martin Hope
igorbcm
Asked: 2025-01-04 22:20:22 +0000 UTC
  • 6

有一个输入复选框

<input type="<?php echo esc_attr($type == 'tabs_radio' ? "radio" : "checkbox") ?>" <?php checked($checked) ?> name="woof_section_tabs" class="input-rst-btn" id="woof_tab_<?php echo esc_attr($key . "_" . $id); ?>">

输出看起来像：

<input type="checkbox" name="woof_section_tabs" class="input-rst-btn" id="woof_tab_pa_product-category_67793e016ad43">

并且有一个标签

<label class="woof_section_tab_label" for="woof_tab_pa_product-category_67793e016ad43" id="woof_pa_product-category_67793e016ad43_content">

当您单击复选框时，其标签可以设置为选中的样式，这样可以：

.woof_redraw_zone input[name="woof_section_tabs"]:checked + label.woof_section_tab_label {
    position: absolute;
    top: 75px;
    right: 0;
    z-index: 21;
}

还有一个div（在input之前，一个parent），当input[name="woof_section_tabs"]:勾选时需要改变样式，我写

.woof_redraw_zone input[name="woof_section_tabs"]:checked + .rst-btn (класс DIVa) {
    position: absolute;
    top: 75px;
    right: 0;
    z-index: 21;
}

块本身

<div class="woof_submit_search_form_container rst-btn" id="rst-btn"><a href="/" class="rst-butt"><div class="reset-in-filter" data-link="">Текст</div></a></div>

而且根本不行，我也通过js尝试过

var obj1 = document.getElementsByClassName('woof_section_tab_label');
if (getComputedStyle(obj1).position == 'absolute') {
document.getElementsByClassName('woof_submit_search_form_container').style.position = 'absolute';
}

那些。事实证明，当 input:checked 时，div 块需要分配位置：absolute，使用标签本身可以正常工作。他不想去找女主角。请帮忙解决，css和脚本都可以。

javascript
Martin Hope
Даниил Королев
Asked: 2025-01-04 19:46:06 +0000 UTC
  • 5

在RoR中的数据库表中创建请求时，抛出此错误：

缺少 Zayavk#sotrudnikis 关联的模型类 Sotrudnikis。您可以使用 :class_name 选项指定不同的模型类。

这个模型是存在的，甚至连联系都被阐明了。这里可能出了什么问题？

class Zayavk < ApplicationRecord   
  belongs_to :sotrudnikis   
  belongs_to :kii_objs   
  belongs_to :incidents_types   
  belongs_to :zayavka_statuses 
end 

class Sotrudniki < ApplicationRecord   
  belongs_to :dolznosti   
  belongs_to :role   
  validates :s_name, presence: true, uniqueness: true 
  has_secure_password 
end

# Части кода контроллера, выдающего ошибку: 
def create     
  @zayavk = Zayavk.new(zayavk_params) 
       
  respond_to do |format|       
    if @zayavk.save         
      format.html { redirect_to @zayavk, notice: "Zayavk was successfully created." }         
      format.json { render :show, status: :created, location: @zayavk }       
    else         
      format.html { render :new, status: :unprocessable_entity }         
      format.json { render json: @zayavk.errors, status: :unprocessable_entity }       
    end     
  end   
end
ruby-on-rails
Martin Hope
Michael
Asked: 2025-01-04 17:55:52 +0000 UTC
  • 5

我正在编写一个程序，使用最速下降法计算非线性方程的根。我在寻找导数时也遇到了问题（我将附上屏幕截图以更清楚地说明我在说什么）。我想使用numpy和sumpy方法，但由于距离考试时间不多，所以我匆忙地写了代码。

第一种情况是 x1 = -0.9，x2 = 0.7（根应该精确到 10^-6：x1 = -0.947718 和 x2 = 0.713550，但是却找到了完全不同的根）。

第二种情况是x1 = -0.1，x2 = 2.2（根必须精确到10^-6：x1 = -0.110086和x2 = 2.222477，就像牛顿法中的情况一样）。

非线性方程组：

非线性方程组

方程根的图形定位：

方程根的图形定位

该理论可以在这里看到：

最速下降法，第 1 页

最速下降法，第 2 页

我尝试解这个方程： 图3

程序代码，起点（-0.9，0.7）：

import math

# первый корень
x1k = -0.9
x2k = 0.7

# второй корень
##x1k = -0.1
##x2k = 2.2

alpha = 0.25

##    fx1_x1k_x2k = round(2 * (math.cos(x1k + 1.5) * (math.sin(x1k + 1.5) + 2.9 - x2k) + x1k + math.cos(x2k - 2)), 6)
##    fx2_x1k_x2k = round(-2 * ((math.cos(x2k - 2) * math.sin(x2k - 2)) - x2k + math.sin(x1k + 1.5) + 2.9 + (x1k * math.sin(x1k + 1.5))), 6)

for k in range(1, 39):
    fx1_x1k_x2k = round((2 * math.sin(x1k + x2k) * math.cos(x1k + x2k)) + (3.38 * x1k) - (2.6 * math.sin(x1k + x2k)) - (2.6 * x1k * math.cos(x1k + x2k)) - (2 * math.cos(x1k + x2k)) + 2.6, 6)
    fx2_x1k_x2k = round(4 * x1k**3 + 0.16 * x2k**3 + (0.8 * x2k * x1k**2) + (0.4 * x2k**2 * 2 * x1k) - 4 * x1k - 0.8 * x2k, 6)
    
    x1_current = round(x1k - alpha * fx1_x1k_x2k, 6)
    x2_current = round(x2k - alpha * fx2_x1k_x2k, 6)

    print(f'------------------------------------ k = {k} ------------------------------------')
    
    print(f'x1_current = {x1_current}')
    print(f'x2_current = {x2_current}')

    print(f'|x1 - x1_current| = {round(abs(x1k - x1_current), 6)}')

    x1k = x1_current
    x2k = x2_current

找到第一个根的结果，我们得到 (-0.110084, 2.222471)，而不是 (-0.947718, 0.713550)，其中 k = 38：

------------------------------------ k = 1 ------------------------------------
x1_current = -0.904586
x2_current = 0.63008
|x1 - x1_current| = 0.004586
------------------------------------ k = 2 ------------------------------------
x1_current = -0.920633
x2_current = 0.550413
|x1 - x1_current| = 0.016047
------------------------------------ k = 3 ------------------------------------
x1_current = -0.950972
x2_current = 0.475969
|x1 - x1_current| = 0.030339
------------------------------------ k = 4 ------------------------------------
x1_current = -0.996371
x2_current = 0.432886
|x1 - x1_current| = 0.045399

...

------------------------------------ k = 38 ------------------------------------
x1_current = -0.110084
x2_current = 2.222471
|x1 - x1_current| = 1e-06

程序代码，起点（-0.1，2.2）：

import math

# первый корень
##x1k = -0.9
##x2k = 0.7

# второй корень
x1k = -0.1
x2k = 2.2

alpha = 0.25

##    fx1_x1k_x2k = round(2 * (math.cos(x1k + 1.5) * (math.sin(x1k + 1.5) + 2.9 - x2k) + x1k + math.cos(x2k - 2)), 6)
##    fx2_x1k_x2k = round(-2 * ((math.cos(x2k - 2) * math.sin(x2k - 2)) - x2k + math.sin(x1k + 1.5) + 2.9 + (x1k * math.sin(x1k + 1.5))), 6)

for k in range(1, 39):
    fx1_x1k_x2k = round((2 * math.sin(x1k + x2k) * math.cos(x1k + x2k)) + (3.38 * x1k) - (2.6 * math.sin(x1k + x2k)) - (2.6 * x1k * math.cos(x1k + x2k)) - (2 * math.cos(x1k + x2k)) + 2.6, 6)
    fx2_x1k_x2k = round(4 * x1k**3 + 0.16 * x2k**3 + (0.8 * x2k * x1k**2) + (0.4 * x2k**2 * 2 * x1k) - 4 * x1k - 0.8 * x2k, 6)
    
    x1_current = round(x1k - alpha * fx1_x1k_x2k, 6)
    x2_current = round(x2k - alpha * fx2_x1k_x2k, 6)

    print(f'------------------------------------ k = {k} ------------------------------------')
    
    print(f'x1_current = {x1_current}')
    print(f'x2_current = {x2_current}')

    print(f'|x1 - x1_current| = {round(abs(x1k - x1_current), 6)}')

    x1k = x1_current
    x2k = x2_current

当 k = 21 时，求二阶根的结果是 (-0.110084, 2.222471)：

------------------------------------ k = 1 ------------------------------------
x1_current = -0.106128
x2_current = 2.20748
|x1 - x1_current| = 0.006128
------------------------------------ k = 2 ------------------------------------
x1_current = -0.105683
x2_current = 2.212223
|x1 - x1_current| = 0.000445
------------------------------------ k = 3 ------------------------------------
x1_current = -0.108148
x2_current = 2.215606
|x1 - x1_current| = 0.002465
------------------------------------ k = 4 ------------------------------------
x1_current = -0.108136
x2_current = 2.217791
|x1 - x1_current| = 1.2e-05

...

------------------------------------ k = 21 ------------------------------------
x1_current = -0.110084
x2_current = 2.222471
|x1 - x1_current| = 1e-06
python
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