主页 / 问题 / 897810
Accepted
Puvvl
Asked:2020-10-25 20:55:45 +0000 UTC2020-10-25 20:55:45 +0000 UTC

合并数组元素[重复]

  • 772

您需要找到所有重复项products.id并合并quantity。结果应该是这样的：

products = [{id: 5, quantity: 25}, {id: 3, quantity: 15}, {id: 4, quantity: 164}]


const arr = [{
    id: 1,
    products: [{
      id: 5,
      quantity: 5
    }, {
      id: 3,
      quantity: 2
    }]
  },
  {
    id: 2,
    products: [{
      id: 4,
      quantity: 75
    }, {
      id: 5,
      quantity: 20
    }]
  },
  {
    id: 3,
    products: [{
      id: 3,
      quantity: 13
    }, {
      id: 4,
      quantity: 89
    }]
  },
]

let allProducts = [];
let products = [];

function getAllProducts() {
  arr.forEach(value => {
    value.products.forEach(product => allProducts.push(product))
  })
  concatProducts(allProducts)
}

function concatProducts(arr) {
  arr.reduce(function(a, b) {
    return a.id === b.id ? products.push({
      id: a.id,
      quantity: a.quantity + b.quantity
    }) : products.push(b);
  });
  console.log(products)
}

getAllProducts()

javascript

2 个回答

  1. Best Answer

    const arr = [
  {
    id: 1,
    products: [
      {id: 5, quantity: 5},
      {id: 3, quantity: 2}
    ]
  }, {
    id: 2,
    products: [
      {id: 4, quantity: 75},
      {id: 5, quantity: 20}
    ]
  }, {
    id: 3,
    products: [
      {id: 3, quantity: 13},
      {id: 4, quantity: 89}
    ]
  }
];

function getAllProducts(arr) {
  const allProducts = {};
  arr.forEach(value => {
    value.products.forEach(prod => {
      if (allProducts[prod.id] === undefined)
        allProducts[prod.id] = prod.quantity;
      else
        allProducts[prod.id] += prod.quantity;
    });
  })
  const products = [];
  for (let id in allProducts) {
    products.push({id: id, quantity: allProducts[id]});
  }
  return products;
}

console.log(getAllProducts(arr));

    • 1 

  2. const arr = [{
    id: 1,
    products: [
      { id: 5, quantity: 5 }, 
      { id: 3, quantity: 2 }
    ]
  },
  {
    id: 2,
    products: [
      { id: 4, quantity: 75 },
      { id: 5, quantity: 20 }
    ]
  },
  {
    id: 3,
    products: [
      { id: 3, quantity: 13 }, 
      { id: 4, quantity: 89 }
    ]
  },
]

var res = arr.reduce((res, item) => {
  item.products.reduce((res, item) => {
    if (!res[item.id])
      res[item.id] = 0;
    res[item.id] += item.quantity;
    return res;
  }, res);
  return res;
}, {});

var result = [];
for (var key in res)
  result.push({ id: +key, quantity: res[key]});
  
console.log(result);

    • 1

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