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Vladimir
Asked:2020-09-26 18:21:16 +0000 UTC2020-09-26 18:21:16 +0000 UTC

从 html 文档中获取链接

  • 772

我想不通如何从文章标签中使用正则表达式获取data-file-url属性的值，即获取链接 https://data/image.png。

<article id="post_299290" class="post-preview blacklisted" data-id="299290"   data-approver-id="35"  data-width="2528" data-height="2924" 
    data-flags=""  data-score="0" data-fav-count="9" data-file-ext="png"  data-normalized-source="" data-is-favorited="false"  
    data-file-url="https://data/image.png" data-uploader-id="39" data-large-file-url="https://data/sample/sample-image.jpg" data-preview-file-url="https://data/preview/image.jpg"/>
c#

2 个回答

  1. Best Answer

    这是不检查标签的情况：

    (?<=data-file-url=")[^"]*

    测试https://regexr.com/5crdk

    从

    <article id="post_299290" class="post-preview blacklisted" data-id="299290"   data-approver-id="35"  data-width="2528" data-height="2924" 
    data-flags=""  data-score="0" data-fav-count="9" data-file-ext="png"  data-normalized-source="" data-is-favorited="false"  
    data-file-url="https://data/image.png" data-uploader-id="39" data-large-file-url="https://data/sample/sample-image.jpg" data-preview-file-url="https://data/preview/image.jpg"/>

    会发现

    https://data/image.png
    • 1

  2. 您可以尝试 VS Regex Editor 扩展 - 对模式非常有帮助

    var input = "<article id=\"post_299290\" class=\"post-preview blacklisted\" data-id=\"299290\"   data-approver-id=\"35\"  data-width=\"2528\" data-height=\"2924\" \r\n    data-flags=\"\"  data-score=\"0\" data-fav-count=\"9\" data-file-ext=\"png\"  data-normalized-source=\"\" data-is-favorited=\"false\"  \r\n    data-file-url=\"https://data/image.png\" data-uploader-id=\"39\" data-large-file-url=\"https://data/sample/sample-image.jpg\" data-preview-file-url=\"https://data/preview/image.jpg\"/>";
           
var regex = new Regex(@"data-file-url=""(\b(?:https?://|www\.)\S+\b)*""");
var matches = regex.Matches(input);

var links = matches.Select(x => x.Groups[1].Value);
    • -1

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